Question

i
$(9n ^{2} + 6n + 1) \div 3$
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Answer 1

Answer:

answer for the given problem is given

Answer 2

Step-by-step explanation:

$\frac{{9n}^{2} + 6n + 1}{3} \\ \\ = \frac{ {9n}^{2} + 3n + 3n + 1 }{3} \\ \\ = \frac{3n(3n + 1) + 1(3n + 1)}{3} \\ \\ = \frac{(3n + 1)(3n + 1)}{3} \\ \\ = \frac{3 {(n + 1)}^{2} }{3} \\ \\ = {(n + 1)}^{2} \\ \\ Hope \: it \: helps \: you...... \\ Please \: mark \: my \: answer \: as \: \\ brainleist......$