Question

(i)
$(\sqrt{6)} ^{x - 2} = 1$
(ii)
$( \sqrt{2)} \: ^{x} = {2}^{8}$
Now solve it

Answer 1

(ii) $(\sqrt{2}) ^{x} = 2 ^{8}$

$2 ^{x/2} = 2^{8}$

x/2 = 8

x = 16

Answer 2

here is your answer

2) √2)^x = 2^8

2 ^ x/2 = 2^8
so, x/2= 8.
x = 16 ans.

1)
$\sqrt{6 }^{x - 2} = 1$
$\sqrt{6} {}^{x - 2} \: = \sqrt{6} { }^{0 } \\ so \: x - 2 = 0 \\ so \: \: x = 2 \: answer.$
☺hope it helps u☺