Question

I the air density were uniform, then the height of the atmosphere above the
atmospheric pressure of Iox 10Pa is (density of air is 1.3 kg/m.g= lone
10.77km
2) 7.7 km
3) 77km
An airtight container hm
sphere above the sea level to produce a normal
119
) 0.077km
Ifa​

Answer 1

Answer:

Explanation:

Dear Student,

Pressure due to atmosphere:P=hdg

Then, height is h=Pdg=1×1051.3×10=7692. 3 m

Ans: 7692.3 m=7.7km

Answer 2

Answer:h=pdf

1×1051.3×10

7692.3

Explanation: