Question

i)
The difference between the two natural numbers is 12 and the difference between their squares is 600.
Find the sum of these two numbers. Also find the numbers.​

Answer 1

Correct answer are$(a + b)= 50$,

$a = 31$ and $b = 19$

Explanation:

Let, two numbers are a  and b

Given that,

$a - b = 12$…….(i)

$a^{2} - b^{2} = 600$

We know that, $a^{2} - b^{2} = (a - b)(a + b)$

$(a - b)(a + b)= 600$

$(a + b) = \frac{600}{12}$

$(a + b)= 50$…………..(ii)

On adding equation (i) and (ii), we get

$2a = 62$  

$a = 31$

Now put the value in (ii),

$b = 50 - 31 = 19$.