Question

i the figure,AC:4.2 cm,BC:10 cm and 0 is the centre of circle.find the area of shaded region.(π=3.14).

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Heyy mate ❤✌✌❤

Here's your Answer.....

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AREA OF SHADED REGION = AREA OF SEMICIRCLE- AREA OF TRIANGLE.

In Triangle ABC, By Pythagoras thm,

AB^2 = AC^2 + BC^2

AB^2 = 4.2^2 + 10^2

AB^2 = 17.64 + 100

AB^2 = 117.64

AB= 10.84

Area of Triangle= 1/2 × base × height

= 1/2 × 10 × 4.2

= 5 × 4.2

= 21cm^2.

Area of Semicircle =( Pie × r^2 )/2

= 3.14 × 5.42 × 5.42/2

= 3.14 × 2.76 × 5.42

= 46.97cm^2

Area of shaded region= 46.97 - 21

= 25.97cm^2
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