i the figure attached AB =AC THE CIRCLE PASSING P TOUCHES THE SIDE AC OF ITS MIDPOINT D THIS CIRCLE INTERSECT AB AT P PROVE THAT AB = 4×AP
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Answer:
A
D
2
=
A
P
⋅
A
B
Given
A
B
=
A
C
,
and
D
is midpoint of
A
C
,
⇒
A
D
=
A
C
2
=
A
B
2
⇒
(
A
B
2
)
2
=
A
P
⋅
A
B
⇒
(
A
B
)
2
4
=
A
P
⋅
A
B
⇒
A
B
=
4
A
P
Hence
4
A
P
=
A
B
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Answer:
i the figure attached AB =AC THE CIRCLE PASSING P TOUCHES THE SIDE AC OF ITS MIDPOINT D THIS CIRCLE INTERSECT AB AT P PROVE THAT AB = 4×AP
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