Question

i) The number of terms in the expansion of (1 + 6x + 9x2)23
are​

Answer 1

Answer:

Taking ‘x’ common, we get (1 – 3x + 3x^2)^20.

Now, in the expansion, highest and lowest powers of x will be 40 and 0 respectively.

And since it has continuous powers of x (0,1 and 2), the expansion will have all the powers of x ranging from 0 to 40.

Therefore, the no. of terms in the expansion will be 41.