Question

I. The odometer of a car reads 2500km at the Start of a trip and 4000 km at the end of the trip. If the Trip took 8 hr Calculate the Average speed of the car in Kmh and ms.​

Answer 1

Given :

Initial reading = 2500km

Final reading = 4000km

Time of journey = 8hr

To Find :

Average speed of car in km/hr and m/s.

Solution :

❖ Average speed of body is defined as the ratio of total distance travelled to the total time taken.

• It is a scalar quantity having only magnitude.
• It can't be negative.
• SI unit : m/s
• Dimension formula : [L¹T‾¹]

$\sf:\implies\:V_{av}=\dfrac{R_{final}-R_{initial}}{Time}$

$\sf:\implies\:V_{av}=\dfrac{4000km-2500km}{8hr}$

$\sf:\implies\:V_{av}=\dfrac{1500}{8}$

$:\implies\:\underline{\boxed{\bf{\red{V_{av}=187.5\:km/hr}}}}$

We know that, 1 km/hr = 5/18 m/s

∴ 187.5 km/hr = 187.5 × 5/18

$:\implies\:\underline{\boxed{\bf{\orange{V_{av}=52.08\:ms^{-1}}}}}$

Answer 2

Given :

Initial reading = 2500km

Final reading = 4000km

Time of journey = 8hr

To Find :

Average speed of car in km/hr and m/s.

Solution :

❖ Average speed of body is defined as the ratio of total distance travelled to the total time taken.

It is a scalar quantity having only magnitude.

It can't be negative.

SI unit : m/s

Dimension formula : [L¹T‾¹]

$\sf:\implies\:V_{av}=\dfrac{R_{final}-R_{initial}}{Time}$

$\sf:\implies\:V_{av}=\dfrac{4000km-2500km}{8hr}$

$\sf:\implies\:V_{av}=\dfrac{1500}{8}$

$:\implies\:\underline{\boxed{\bf{\red{V_{av}=187.5\:km/hr}}}}$

We know that, 1 km/hr = 5/18 m/s

∴ 187.5 km/hr = 187.5 × 5/18

$:\implies\:\underline{\boxed{\bf{\orange{V_{av}=52.08\:ms^{-1}}}}}$