Question

i) The parallel sides of a trapezium are 12m and 8 m and the distance between them is 6m. Find the area.
13
ii) If the perimeter of a rhombus is 56 cm and the length of one of its diagonal is equal to 26 cm, then find the
length of the other diagonal.


please help me ​

Answer 1

Step-by-step explanation:

1 answer - 6m

2answer - idk

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Answer 2

Step-by-step explanation:

Solution 1:-

The parallel sides of the AP are 12m and 8m

The distance between the parallel sides = 6m

i.e Height of the trapezium = 6m

Area of the trapezium = ½ × (sum of parallel sides) × Height

= ½ × (12 + 8) × 6

= ½ × 20 × 6

= 10 × 60

= 600

∴ Area of the trapezium = 600m²

Solution 2:-

Perimeter of rhombus  = 56cm

One of the diagonal of the rhombus (d₁) = 26cm

Perimeter of rhombus = $\rm 2\sqrt{(d_{1})^{2} + (d_{2})^{2}}$

$\rm \dashrightarrow \dfrac{56}{2} = \sqrt{26^{2} + (d_{2})^{2}}$

$\rm \dashrightarrow 28 = \sqrt{676+ (d_{2})^{2}}$

$\rm Squaring \: on \: both\: sides$

$\rm \dashrightarrow 28^{2} = 676+ (d_{2})^{2}$

$\rm \dashrightarrow 28^{2} = 676+ (d_{2})^{2}$

$\rm \dashrightarrow 784 = 676+ (d_{2})^{2}$

$\rm \dashrightarrow (d_{2})^{2} = 784 - 676$

$\rm \dashrightarrow (d_{2})^{2} = 108$

$\rm \dashrightarrow d_{2} = \sqrt{108}\approx 10.39$

∴ Length of other diagonal ≈ 10.39cm