Question

i)The particle performing uniform circular motion of radius r=3cm.To find angular acceleration.​

Answer 1

Explanation:

द पार्टिकल परफॉर्मिंग यूनिफॉर्म सर्कुलर मोशन ऑफ रेडियस r=3 cm टू फाइंड एंगुलर एक्सीलरेशन

Answer 2

Given:

Radius of circular path r = 3 cm.

To find:

Angular acceleration ?

Calculation:

Let's assume that the particle is undergoing UNIFORM CIRCULAR MOTION with velocity 'v'.

Angular Acceleration is defined as moment of linear acceleration in a circular trajectory.

$\vec{ \alpha } = \vec{r} \times \vec{a}$

$\implies \alpha =r \times a \times \sin( \theta)$

• $\theta$ radius vector and the acceleration vector.
• Also , in this case , $\theta$ = 90°.

$\implies \alpha =r \times a \times \sin( {90}^{ \circ} )$

$\implies \alpha =r \times a$

$\implies \alpha =3 \times a_{c}$

$\implies \alpha =3 \times \dfrac{ {v}^{2} }{r}$

$\implies \alpha = \dfrac{3 {v}^{2} }{r}$

So, final answer is :

$\boxed{ \bf\alpha = \dfrac{3 {v}^{2} }{r} }$