(i) the point (−3, 2) lies on the line ax + 3y + 6 = 0, calculate the value of a.
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(-3,2) are the points of line ax+3y+6 = 0
So, x = -3 and y = 2
Placing the value of x and y in the given equation.
Therefore, a(-2) + 3(2) + 6 = 0
Therefore, -2a + 6 + 6 = 0
So, -2a + 12 = 0
Now -2a = -12
This, a = -12/-2
This, a= 6
Therefore the value of a is 6
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(-3,2) are the points of line ax+3y+6 = 0
So, x = -3 and y = 2
Placing the value of x and y in the given equation.
Therefore, a(-2) + 3(2) + 6 = 0
Therefore, -2a + 6 + 6 = 0
So, -2a + 12 = 0
Now -2a = -12
This, a = -12/-2
This, a= 6
Therefore the value of a is 6
HOPE IT HELPS YOU.
PLZ MARK THIS ANSWER AS BRAINLIEST
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