(i) The runs scored by a batsman in 5 ODIs are 31, 97, 112, 63, and 12. Find the standard deviation
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Given : The runs scored by a batsman in 5 ODIs are 31, 97, 112, 63, and 12.
To Find : the standard deviation
Solution:
Mean = ( 31 + 97 + 112 + 63 + 12) / 5
= 315/5
= 63
∑(x - mean)² = ( 31 - 63)² + (97 - 63)² + (112 - 63)² + (63 - 63)² + (12 - 63)²
= 1024 + 1156 + 2401 + 0 + 2601
= 7182
SD = √7182/5
≈ 37.9
standard deviation is about 37.9
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