Question

(i) The sum of a two-digit number and the number obtained by reversing its digit
is 143. Find the number, if its tens place digit is greater than the units place
digit by 3.​

Answer 1

Answer:

The sum of 2 digit number and the number obtained by reversing the order of the digit is 165. If the digit differ by 3, find the number , when ten's digit is bigger than the unit 's digit. Hence both the conditions are verified. 96 is the required number.

After interchanging the digits the number becomes 10x + y. Given that two digit number and the number with digits interchanged add up to 143. Also, in the given number the digit in unit's place is 3 more than the digit in the ten's place. Thus, the number is 58.