Question

(i) The sum of the angle of polygon. whose sides are n is ______
(ii) The length of square whose are 441cm2 is__________​

Answer 1

Answer:

1.We know that if a polygon has 'n' sides, then it is divided into (n – 2) triangles. We also know that, the sum of the angles of a triangle = 180°. Therefore, the sum of interior angles of a polygon having n sides is (2n – 4) right angles. Thus, each interior angle of the polygon = (2n – 4)/n right angles.

2.Side of the square= S^2

(441)^2=S^2

(21)^2=S^2

21=S

side of a square is 21....

Answer 2

Answer:

(I) (2n-4) n

(ii) 21m

EXPLANATION :

Area =(side)

Area =(side) 2

Area =(side) 2

Area =(side) 2 =441m

Area =(side) 2 =441m 2

Area =(side) 2 =441m 2

Area =(side) 2 =441m 2 21

Area =(side) 2 =441m 2 212∣

Area =(side) 2 =441m 2 212∣ 4

Area =(side) 2 =441m 2 212∣ 4ˉ

Area =(side) 2 =441m 2 212∣ 4ˉ

41

41ˉ

41ˉ

41ˉ

41ˉ

41ˉ ∣−4

41ˉ ∣−441∣41

41ˉ ∣−441∣41

41ˉ ∣−441∣41

41ˉ ∣−441∣41 ∣−41

41ˉ ∣−441∣41 ∣−41

41ˉ ∣−441∣41 ∣−41

41ˉ ∣−441∣41 ∣−41 ∣0

41ˉ ∣−441∣41 ∣−41 ∣0∴Side=

41ˉ ∣−441∣41 ∣−41 ∣0∴Side= 441

41ˉ ∣−441∣41 ∣−41 ∣0∴Side= 441

41ˉ ∣−441∣41 ∣−41 ∣0∴Side= 441 m

41ˉ ∣−441∣41 ∣−41 ∣0∴Side= 441 m=21m