Question

i) The sum of the digits of a two-digit number is 9. Also, nine times this number is
twice the number obtained by reversing the order of the digits. Find the number.​

Answer 1

ANSWER:-

Let the ten's digit no. be x and one's digit no. be y.

So the no. will be = 10x+y.

Given : x+y=9-----(I)

9(10x+y)=2(10y+x) ⇒88x−11y=0 -----(II)

On solving I and II simultaneously you will get x=1 and y=8.

Therefore your desired no. is 18

ADDITIONAL INFORMATION:-

• HOW TO REVERSE A NUMBER?

The modulo operator (%) returns the remainder of a divison. In this case, we divide number by 10 and return the remainder. Consider the integer 1234. ... The remainder of the division will be 4 representing the ones column which could not be divided by 10.