Question

I The taxi charges in a city consist of a fixed charge together with the charge for the
distance covered. For a distance of 10 km, the charge paid is 105 and for a
joumey of 15 km, the charge paid is * 155. What are the fixed charges and the
charge per km? How much does a person have to pay for travelling a distance of
25 km?
umerator and the denominator.​

Answer 1

Answer:

Let fixed charges be x and charge for per km be y.

A.T.Q.

1st Condition:

x+10y = 105

2nd Condition :

x + 15y = 155

From equation (1), we get

x= 105 - 10y

Putting this value in equation (ii), we have

105-10y + 15y = 155

105 + 5y = 155

➡ 5y = 155-105

5y = 50 = 10

Now, puttingy = 10 in equation (i), we have + 10(10) = 105

= x+100 = 105

=5

Fixed charges is 5 and charges per km is 10.

3rd Condition:

For distance of 25 km

x+ 25y

= 5+25(10)

5+ 250

= 255

Amount paid for travelling 25 km is 255.

Step-by-step explanation:

Hope it helps you dear (◍•ᴗ•◍)