(i) The value of acceleration due to gravity on the surface of the moon is (Take mass of the moon=7.4*10²² kg , radius of moon = 1740 * 10³ * m and G=6.7*10² Nm² /kg²
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Answer:
The pressure= 1.47×104 N m−2
B
The trust at the base level=147 N
Explanation:
Pressure =ρgh
where ρ=density of water
g=acceleration due to gravity
P=103×9.8×1.5=1.47×104Nm2
Upthrust = Force exerted = Pressure \times Area
⇒Upthrust=1.47×104Nm2×100×10−4m=147N
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