i think its ncert question. from chapter current and electricity ... there is a combination of four resistance 4,10,4,9 ohm calculate the potential difference between point P and Q
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what is the current which flow in circuit.
r=r1+r2+r3+r4..and so on 7
therefore ,
r=4+10+4+9
=27 ohms
therefore.
equivalent resistance =27 ohms
and, current =2.4A [given ]
from ohm's law. v=ir
=2.4x27
=64.8 volt
hope it helps you..
pls mark me as brainliest .
r=r1+r2+r3+r4..and so on 7
therefore ,
r=4+10+4+9
=27 ohms
therefore.
equivalent resistance =27 ohms
and, current =2.4A [given ]
from ohm's law. v=ir
=2.4x27
=64.8 volt
hope it helps you..
pls mark me as brainliest .
ehsan2:
bye
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