Question

I think no one don't know this questions 4/(√11-√7) rationalise the denominator

Answer 1

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4/(√11-√7) rationalise the denominator

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$\frac{4}{( \sqrt{11} - \sqrt{7}) }$

$= \frac{4}{( \sqrt{11} - \sqrt{7}) } \times \frac{( \sqrt{11} - \sqrt{7} )}{( \sqrt{11} - \sqrt{7} )}$

$= \frac{4( \sqrt{11} - \sqrt{7} ) }{({ \sqrt{11} - \sqrt{7} ) }^{2} }$

$= \frac{4 \sqrt{11} - 4 \sqrt{7} }{11 - 7}$

$= \frac{4 \sqrt{11} - 4 \sqrt{7} }{4}$

$\therefore rationalised$

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Answer 2

Answer:

4/(√11-√7)

⇒  4/(√11-√7) ×(√11+√7) / (√11+√7)

⇒  4 (√11+√7) / (11)² - (7)²

⇒  4(√11-√7) / 121 - 49

⇒  4(√11 -√7) / 72

⇒  (√11-√7) / 18