Question

I think of a number and subtract five from four times the number. the result is 3more than twice the number that I thought of find the number....​

Answer 1

let x be the number you’re thinking of.

let x be the number you’re thinking of.When you divide the number by 3 you have x/3

let x be the number you’re thinking of.When you divide the number by 3 you have x/3When you add 5 to that number you have x/3 +5

let x be the number you’re thinking of.When you divide the number by 3 you have x/3When you add 5 to that number you have x/3 +5And this (x/3+ 5) is equal to twice the original number (2x)

let x be the number you’re thinking of.When you divide the number by 3 you have x/3When you add 5 to that number you have x/3 +5And this (x/3+ 5) is equal to twice the original number (2x)So…

let x be the number you’re thinking of.When you divide the number by 3 you have x/3When you add 5 to that number you have x/3 +5And this (x/3+ 5) is equal to twice the original number (2x)So…x/3 +5 = 2x

let x be the number you’re thinking of.When you divide the number by 3 you have x/3When you add 5 to that number you have x/3 +5And this (x/3+ 5) is equal to twice the original number (2x)So…x/3 +5 = 2xyou need to solve for x. Multiply both side of the equation by 3 to give you

let x be the number you’re thinking of.When you divide the number by 3 you have x/3When you add 5 to that number you have x/3 +5And this (x/3+ 5) is equal to twice the original number (2x)So…x/3 +5 = 2xyou need to solve for x. Multiply both side of the equation by 3 to give youx + 15 = 6x

let x be the number you’re thinking of.When you divide the number by 3 you have x/3When you add 5 to that number you have x/3 +5And this (x/3+ 5) is equal to twice the original number (2x)So…x/3 +5 = 2xyou need to solve for x. Multiply both side of the equation by 3 to give youx + 15 = 6xsubtract x from both sides of the equation to give you:

let x be the number you’re thinking of.When you divide the number by 3 you have x/3When you add 5 to that number you have x/3 +5And this (x/3+ 5) is equal to twice the original number (2x)So…x/3 +5 = 2xyou need to solve for x. Multiply both side of the equation by 3 to give youx + 15 = 6xsubtract x from both sides of the equation to give you:15 = 5x

let x be the number you’re thinking of.When you divide the number by 3 you have x/3When you add 5 to that number you have x/3 +5And this (x/3+ 5) is equal to twice the original number (2x)So…x/3 +5 = 2xyou need to solve for x. Multiply both side of the equation by 3 to give youx + 15 = 6xsubtract x from both sides of the equation to give you:15 = 5xdivide by 5 to get x = 3

let x be the number you’re thinking of.When you divide the number by 3 you have x/3When you add 5 to that number you have x/3 +5And this (x/3+ 5) is equal to twice the original number (2x)So…x/3 +5 = 2xyou need to solve for x. Multiply both side of the equation by 3 to give youx + 15 = 6xsubtract x from both sides of the equation to give you:15 = 5xdivide by 5 to get x = 3Your original number is 3.

let x be the number you’re thinking of.When you divide the number by 3 you have x/3When you add 5 to that number you have x/3 +5And this (x/3+ 5) is equal to twice the original number (2x)So…x/3 +5 = 2xyou need to solve for x. Multiply both side of the equation by 3 to give youx + 15 = 6xsubtract x from both sides of the equation to give you:15 = 5xdivide by 5 to get x = 3Your original number is 3.Check by running it through the original statement:

let x be the number you’re thinking of.When you divide the number by 3 you have x/3When you add 5 to that number you have x/3 +5And this (x/3+ 5) is equal to twice the original number (2x)So…x/3 +5 = 2xyou need to solve for x. Multiply both side of the equation by 3 to give youx + 15 = 6xsubtract x from both sides of the equation to give you:15 = 5xdivide by 5 to get x = 3Your original number is 3.Check by running it through the original statement:My number is 3. If I divide by 3 and then add 5 to that I will get 6, which is twice the original number. Problem solved.

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