Question

I think sec(90-theta)=cosec11.
But how you take 21..
Plz explain.

Answer 1

$\bold\:\underline{\boxed{Answer}}$

no

sec(90-∅) ≠ cosec11.

$\bold{\boxed{Explanation}}$

by complementary angles of trigonometry

sec(90-∅) = cosec∅