Question

I think so you can't solve this problem​

Answer 1

${\huge{\pink{\underline{\underline{\purple{\mathbb{\bold{\mathcal{AnSwEr..}}}}}}}}}$

${\large{\blue{\bold{\underline{Given:-}}}}}$

▪︎ AC = BC.

▪︎ AB² = 2AC².

${\large{\blue{\bold{\underline{Theorem\:Used:-}}}}}$

▪︎ Converse of pythagoras theorem.

${\large{\blue{\bold{\underline{Now,}}}}}$

▪︎ It is given that

=》 AB² = 2AC².

=》 AB² = AC²+AC².

=》 AB² = AC²+BC².

{Since AC = BC}

So the given triangle is an isosceles right angle triangle because square of largest side is equal to the sum of the square of two other sides. i.e. by Pythagoras Theorem.

${\large{\blue{\bold{\underline{Therefore, }}}}}$

▪︎ Measure of angle C = 90°

{By converse of pythagoras theorem as the angle opposite to largest side, AB is Angle C.}