Question

I This Question O is the centre of the circle. The radius AO =10cm and perpendicular on chord AB 5 cm. The Measure of AB

Answer 1

I think your question is AB=10 root 5

Answer 2

let ,

ao=10cm

suppose point p is on chord ab is perpendicular

op=5cm

hence triangle opa formed

by using pythagoras theorem

oa^2=op^2+ap^2

(10)^2=25+ap2^2

100-25=ap^2

75=ap^2

taking square root

underroot75=ap

25*3=ap

5 underroot 3=ap

but ab=2ap(perpendicular drawn from centre to bisect the chord

hence ab=2ap

=2*5underroot 3

ab=10 underoot 3cm

but underroot 3=1.73 appro.

so =10*1.73

ab=17.3cm