Question

I to the
gravely
accleration due to
earth ĝ a constart?
Dicuss.​

Answer 1

Answer:

Relationship between g and G :-

Consider a body of mass ( m ) is on the earth surface , mass of the earth ( M ) and the distance between body and mass is R

Therefore according to universal law

F = GMm / R² ===> Eqn 1

From Newton's second law

F = ma = mg ===> Eqn 2 [ due to gravity ]

from eqn 1 and 2

mg = GMm / R²

[ Cancel " m " on both sides ]

g = GM / R²

Here ,

g = acceleration due to gravity

G = gravitational constant

Answer 2

Answer:

Relationship between g and G :-

• Consider a body of mass "m" on the earth .
• Let "R" be the radius of the earth and "m" be the mass of the earth .

• Force acting on the body of mass "m" due to gravitational pull of the earth is F = mg ===> eqn 1

• According to Newton's gravitational law , force on the body of mass "m" is F = GMm / R² ===> eqn 2

• From eq's (1) and (2) , we have
• mg = GMm / R²
• Here "m" gets cancel
• ===> g = GM / R²