I traingle ABC , M and N are midpoints of AB and AC. Pand
Q are midpoints of AM and
AN and PQ=1.6cm then BC=
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Consider the triangle ABC, M and N are the midpoints of the sides AB and AC respectively.
Let AP be the altitude from the vertex A to the side BC.
The line joining the midpoints of AB and AC meet the altitude AP at O.
Required to prove that AO = OP.
So, we have to prove that AO = ½AP
In triangle ABC.
M and N are the midpoints of the sides AB and AC.
So, we have
AM = ½AB; AN = ½ AC
According to the Midpoint Theorem,
MN = ½ BC
So, ΔABC ~ ΔAMN
⇒ Area(AMN) / Area(ABC) = MN2 / BC2
= ( BC/2 )2 / BC2
= 1/4
= AO2 / AP2
So,
AO/AP = 1/2
AO = ½ AP
Hence, AO = OP.
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