Question

i). Two dice are thrown. Find the probability of the following events.

ii). The sum of the numbers on their upper faces is at least 8.

iii). The sum of the numbers on their upper faces is at the most 4.

Answer 1

Dear Mate,

Answer:

1. 5 / 12

2. 1 / 6

Step-by-step explanation:

Sample Space= {(0,1),(0,2),(0,3)....,(6,6)}

n(s) = 36

1. E= {(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)}

n(e)= 15

P(The sum of the numbers on their upper faces is at least 8) = 15 / 36 = 5 / 12

2. E = {(1,1),(1,2),(1,3),(2,1),(2,2),(3,1) }

n(e) = 6

P(The sum of the numbers on their upper faces is at the most 4) = 6 / 36

= 2 / 12 = 1 / 6

This is the general and correct way that is taught in my school

Hope this helps you...

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