Question

(i) Two resistors with resistance of 10 and 15 ohm are connected to a battery of
12V so as to obtain and measure (a) Minimum electric current (b) Maximum
electric current.​

Answer 1

Explanation:

ANSWER

(a) (i) For minimum current we must make R maximum. This can be done by connecting the resistances in series.

(ii) For maximum current we must make R minimum. This can be done by connecting the resistances in parallel.

(b) (i)R

eq

=R

1

+R

2

=5+10=15Ω

I=

R

eq

V

=

15

6

=0.4A

(ii) R

eq

=

R

1

+R

2

R

1

R

2

=

5+10

5×10

=3.33Ω