Question

i) Two roots of quadratic équation are 4 and - 3, frame the equation​

Answer 1

Given:-

Two roots of the quadratic equation = 4 and -3

To find:-

The quadratic equation

Assumption:-

Let us assume the two roots of a quadratic equation to be $\bf{\alpha}$ and $\bf{\beta}$ Where:-

• $\bf{\alpha = 4}$
• $\bf{\beta = -3}$

Solution:-

We know,

A quadratic equation is represented in the form:-

$\bf{x^2 + (\alpha + \beta)x + \alpha \beta}$

Therefore,

$\bf{\underline{Quadratic\:Equation:-}}$

= $\bf{x^2 + [(4) + (-3)]x + 4\times (-3)}$

= $\bf{x^2 + (4-3)x + (-12)}$

= $\bf{x^2 + x -13}$

Therefore the quadratic equation is:-

$\bf{\underline{\boxed{\bf{x^2+x-12}}}}$

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