Question

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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

(maybe this answer is not right) but you can follow the steps to find answers similar to this question

Step-by-step explanation:

$f(x) = 6x^{3} + \sqrt{2} x^{2} -10x - 4\sqrt{2}$

now, its given that $\sqrt{2}$ is a zero of the polynomial f(x)

Therefore,

$x=\sqrt{2}$

i.e. $g(x) = x-\sqrt{2}$

[$f(x) = g(x) *q(x) + r(x)$]

now by dividing $f(x)$ by $g(x)$

we will get,

$q(x) = 6x^{2} + 7\sqrt{2} x +4$

now by solving this quadratic equation, we will get

$x=\frac{-7\sqrt{2}+\sqrt{34} }{12}$ and $x=\frac{-7\sqrt{2}-\sqrt{34} }{12}$

which are the remaining zeroes of f(x).

Hope this helps