Question

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Answer 1

Answer:

Angle EAF= 1/2 of angle BAD, since angle BAD= 2(• + ×) and angle EAF= • + ×

==>∆ABD and ∆ AEF are isosceles triangles. (as it is also given that AB= AD)

==> AC bisects BD and EF.

==>AC is perpendicular to BD and EF.

==> As the same line segment is perpendicular to two other line segments, hence the two line segments i.e. BD and EF are parallel.

[ Hence Proved]

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