Question

I want a rapid answer plzzzzzzz​

Answer 1

${( - 1)}^{4n} \: = \: {( - 1)}^{2n + 2n} \\ = {(- 1)}^{2n \: }{(- 1)}^{2n} \\ = {({(- 1)}^{2})}^{n} \: {({(- 1)}^{2})}^{n} \\ = ({1}^{n} ) \: ({1}^{n} ) \\ = {1}^{n + n} \: = \: {1}^{n} \\ now \: According \: to \: question \\ {( - 1)}^{n} \: + \: {(1)}^{n} \: = \: 0 \\ it \: means \: n \: is \: an \: odd \: number.$

Thankyou!!!