Question

i want a written work plzz

Answer 1

given BP=BO and diagonal BD bisect angle B which is 90 degree. Therefore anglePBO= 45 degree .And side BPand OB equal therefore angle p= angle o .Hence angle pbo +angle p+ angle o= 180
let angle oand p is =x
therefo. angle pbo + p+ o=180
45+x+x=180=67.5degree


at point P
an. bpo +an.opc =180 ( l.p.)
67.5+opc=180
opc =112.5 degree


same processe apply
angle ocp= 45 degree
angle opc = 112.5 degree


Therefore in triangle poc

an.opc + an.ocp + an.cop =180
112.5 +45 +cop =180
cop = 22.5
henced proved