Math, asked by gladiator915, 11 months ago

i want all the trigonometric formulas and ratios​

Answers

Answered by Agashi22
1

Answer:

Step-by-step explanation:

sin∅=perpendicular/hypotenuse

cos∅=base/hypotenuse

tan∅=perpendicular/base

cosecant∅=hypotenuse/perpendicular

secant∅=hypotenuse/base

cotangent∅=base/perpendicular

sin²∅+cos²∅=1

1+tan²∅=sec²∅

1+cot²∅=cosec²∅

sin∅=cos(90-∅)

cos∅=sin(90-∅)

tan∅=cot(90-∅)

cot∅=tan(90-∅)

sec∅=cosec(90-∅)

cosec∅=(90-∅)

Answered by LeuitishaCB
0

Step-by-step explanation:

Sin²x+cos²x=1

Sin²x+cos²x=11+tan²x=sec²x

Sin²x+cos²x=11+tan²x=sec²x1+tan²x=cosec²x

sin2x=2sinx.cosx

sin2x=2sinx.cosxcos2x=cos²x-sin²x

sin2x=2sinx.cosxcos2x=cos²x-sin²xtan2x=2tanx/1-tan²x

sin2x=2sinx.cosxcos2x=cos²x-sin²xtan2x=2tanx/1-tan²xsin3x=3sinx-4sin³x

sin2x=2sinx.cosxcos2x=cos²x-sin²xtan2x=2tanx/1-tan²xsin3x=3sinx-4sin³xcos3x=4Cos³x-3cosx

sin2x=2sinx.cosxcos2x=cos²x-sin²xtan2x=2tanx/1-tan²xsin3x=3sinx-4sin³xcos3x=4Cos³x-3cosxtan3x=3tanx-tan³x/1-3tan²x

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