i want ans to c question
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1) In triangle ABF and triangle ECD
AB=CD(Opposite sides of a parallelogram are equal)
AE=CF
AE+EF=CF+EF
AF=EC
AF=EC
Angle DCE=Angle FAB
From these three we can say that,
Triangle BAF is congruent to triangle ECD
Then,
Angle DEC = Angle BFA
But these both are alternate interior angles of DE and FB.
So DE is parallel to FB.
2) As triangle BAF is congruent to triangle ECD
DE=FB(CPCT rule)
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