Question

i want answer and direct copied answer from internet will be reported ..be aware​

Answer 1

Answer:

Hi your answer is as follows

Step-by-step explanation:

Let one root of given equation is x

Then other root of given equation is x²

Now, product of roots = r.r² = r³ = constant/coefficient of x²

x³ = 27 = 3³

⇒ x = 3

Now, sum of roots = x+ x² = -coefficient of x/coefficient of x² = - k/3

3 + 3² = - k/3

⇒12 × 3 = -k

⇒k = -36

Mark as brainliest if you are satisfied with my answer

Answer 2

Answer:

We have

\tt \alpha = \beta ^2α=β

2

Where alpha and beta are the zeros of Equation

We know that

$$\begin{lgathered}\tt \alpha \times \beta = c/a \\\\ \Rightarrow \tt \beta ^2 \beta = 81/3 \\\\ \tt \Rightarrow \beta ^3 = 27 \\\\ \tt \Rightarrow \beta = 3\end{lgathered}$$

$$\tt So, \alpha = 3^2 =9$$

Now,

We also know that

$$\tt \alpha + \beta = \dfrac{-b}{a}$$

So, replacing values

$$\begin{lgathered}\tt 9+3 = \dfrac{-k}{3} \\\\ \tt \Rightarrow 12 = \dfrac{-k}{3} \\\\ \tt \Rightarrow 12 \times 3 = -k \\\\ \tt \Rightarrow -36 = k\end{lgathered}$$

So, value of k = -36