Question

I want answer ...
Any one know this answer plz plz bto?.

Answer 1

Answer.

[a.] Na2SO4.

Na = +1

O = -2.

So,

Let Oxidation No. of S be x .

then,

(1)×2 + ( x) + (-2)×4 = 0

2 + x -8 = 0

x -6 = 0

x = +6.

NOW

[B.] HNO3

H = +1

O = -2

Let Oxidation No. of N be y.

(+1) + (y) + (-2) ×3 =0

1 + y -6 = 0

y - 5 = 0

y = +5.