Math, asked by RitvikPalaniappan, 4 months ago

i want answer fast and i will mark as brain list who sending correct answer

Attachments:

Answers

Answered by AyushiSingh1102
1

Step-by-step explanation:

(1/cos^2x+1/sin^2x)^1/2=

[(sin^2x+cos^2x)/sin^2xcos^x]1\2=

1/sinxcosx=SecxCosecx = LHL

sinx/cosx+cosx/sinx

=(sin^2x+cos^2x)/sinxcosx

=1/sinxcosx

= secxcosex=RHL

HERE RHL EQUAL TO LHL

Answered by risham90
1

Mark it brilliant......!

Attachments:
Similar questions