i want answer fast and i will mark as brain list who sending correct answer
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Step-by-step explanation:
(1/cos^2x+1/sin^2x)^1/2=
[(sin^2x+cos^2x)/sin^2xcos^x]1\2=
1/sinxcosx=SecxCosecx = LHL
sinx/cosx+cosx/sinx
=(sin^2x+cos^2x)/sinxcosx
=1/sinxcosx
= secxcosex=RHL
HERE RHL EQUAL TO LHL
Answered by
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Mark it brilliant......!
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