Question

I want answer for both a and b with paper explainations​

Answer 1

HERE'S YOUR ANSWER MATE....;

(A.)=

$if \: x = \frac{1}{2}$

then ,

$p( \frac{1}{2} )= 2( \frac{1}{2} ) + 1$

$p( \frac{1}{2} ) = 2$

So , (1/2) is not zero of p(x) as 2≠0

(B.)=>

$eq {}^{n} = > 2 + x + 2 x{}^{2} - x {}^{3}$

for p(0) ;

$= > 2 + (0) + 2(0) {}^{2} - (0) {}^{3}$

$= > 4$

For P(1) ;

$= > 2 + (1) + 2(1) {}^{2} - (1) {}^{3}$

$= > 4$

For P(2) ;

$= > 2 + (2) + 2(2) {}^{2} - (2) {}^{3}$

$= > 4$

HOPE IT'S HELPFUL......:-)