Question

I want answer from a maths genius who knows class 12 very well
I will mark as brainliest
Find the angle of intersection of the curves x^2 + y^2= 4 and (x – 2)^2 + y^2= 4, at the
point in the first quadrant.
i am mad at present tmrw my exam no wrong answer
the correct answer is 60 degrees pls write answer with full steps

Answer 1

as we know that angle or slope = tan(theta)=|(m1-m2/1+m1m2)|

now m1= dy/dx for x^2+y^2=4

m2=dy/dx for (x-2)^2+y^2=4

now solving both the circles we find their point of intersection as (1,√3)

putting the value of x=1 y=√3

in the equation of tan theta

we will get the correct answer

Please try it once you will get d answer