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46 q ans is 11 next is 3 option next is 3 option next is 2 option and last is 1 option
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harshupadhyay29:
Since 5and 7 are remainers respectively of 159ad271. So 159-5=154and 271-7=264 are no which don't remain remainder. So hcf of 154 and 264
264=154×1+110. 154=110×1+44. 110=44×2+22. 44=22×2+0. So answer is 22 (iii) is correct
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