Math, asked by Mrshivam72, 8 months ago

I want answer of my question

Attachments:

Answers

Answered by varun1729
2

Answer:

we know

p (x) = q (x) Γ— g (x) + r (x)

g (x) = p (x) - r (x) / q (x)

g (x) = 3x^3 + x^2 + 2x + 5 - (9x + 10) / 3x-5

= 3x^3 + x^2 - 7x - 5 / 3x - 5

= x^2 + 2x + 1

Answered by Anonymous
0

Answer:

( x+3)(x-3) are the factors of x4+x3-11x2-9x+18

=> ( x+3)(x-3)= x2-32

= x2-9

therefore x2+0x-9 is a factor of x4+x3-11x2-9x+18

therefore dividing x4+x3-11x2-9x+18 by x2+0x-9 =x2+x-2

there fore

x4+x3-11x2-9x+18 = (x2+x-2)(x2-9)

= (x+1)(x-2)(x+3)(x-3)

=> the zeroes of polynomial x4+x3-11x2-9x+18 = -1, 2 , -3, 3

Similar questions
Math, 4 months ago