Question

I want answer of Q 1 b

Answer 1

Molecular weight of Glucose (C6H12O6) is 180g
So 1 mole of Glucose weighs 180g
180g of Glucose contains 6.023 × 10^23 molecules of Glucose .
And in each molecule of Glucose there are 6 C atoms, 12 H atoms and 6 O atoms.

So number of H atoms in 180g of Glucose
= 12 × 6.023 × 10^23=7.227 × 10^24atoms

Number of C atoms in 180g of Glucose
=6 × 6.023 × 10^23=3.613 × 10^24atoms

Number of O atoms in 180g of Glucose
=6 × 6.023 × 10^23=3.613 × 10^24atoms

HOPE IT HELPS.....