Question

I want answer of this question , this question is Available in activity sheet of 10 the std​

Answer 1

the original number is 153

Answer 2

153

Step-by-step explanation:

Answer:

Let the number be abc

So number is 100a+10b+c

= 100a+10b+c = 17(a+b+c)

= 83a=7b+16c  .......(i)

198+100a+10b+c=a+10b+100c

Or

198+99a=99c

hence c-a=2⇒c=a+2 .....(ii)

Also, given a+c=b-1

Now as a+c=b-1  and c=a+2

= a+a+2=b-1

= b=2a+3

now in eq(i)

substitute the values of b and c  

83a=7b+16c

= 83a=7(2a+3)+16(a+2)

= 53a=21+32

= a=1

= b=2a+3=5

= c=a+2=3

So the number is 153