Question

i want answer please ​

Answer 1

$f(x) = {x}^{3}$

$f(x) = y⇒x = {f}^{ - 1} (y)$

$y = {x}^{3}$

$x = y ^{ \frac{1}{3} }$

${f}^{ - 1} (y)= y ^{ \frac{1}{3} }$

${f}^{ - 1} (8)= 2 \times (1) ^{ \frac{1}{3} }$

$Cube \: root \: of \: unity \: of \\ \: (1) \: are \: 1 ,ω \: and \ \: {ω}^{2}$

$f ^{ - 1} (8) = (2,2ω,2 {ω}^{2} )$

Answer 2

Step-by-step explanation:

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