Question

i want argent please​

Answer 1

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The answer of your question is is given in picture.

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Answer 2

Solution:

Given alpha and beta are zeores of given equation,then.

x^2 - 4x +3 = 0.

x^2-x-3x+3 = 0

(x-3)(x-1)=0. ......(1) This means , alpha= 3 or beta = 1. Now in yr question ,3alpha and 3beta are zeroes of quadratic polynomial , then ,equation is:. x^2-(3alpha + 3beta )x+9alpha beta=0 Then x^2- 12x+27=0.[ For alpha and beta value use equation ( 1)] . Required equation is x^2-12x+27=0. I hope it help you ✌️❤️❤️