Question

I want clean explaination

Answer 1

➡️consider 2 cases:

1] when we are pulling the string slowly

2] when we pull it wid a je.rk

in case 1 , the force F with wich we pull the string is equal to the tension of dat string , since we r pulling it slowly , i.e a = 0

so F=T

after drawing FBD , the tension in upper string comes out to be

T1=mg+T= mg +F

so as F increases , T increases .

since T1 is gr8er than T by mg at all times, it will reach its elastic limit first and will break

in case 2 , when we pull it wid a je.rk , the impulse is greater than the elastic limit of the lower string . And b4 it could transfer this impulse to the upper string , it breks .

⏩The Answer is (B)

$The\:Portion\:BC\:of\:the\:string\:will break$

Answer 2

Heya,$<b>$

consider 2 cases:

1] when we are pulling the string slowly

2] when we pull it wid a je.rk

in case 1 , the force F with wich we pull the string is equal to the tension of dat string , since we r pulling it slowly , i.e a = 0

so F=T

after drawing FBD , the tension in upper string comes out to be

T1=mg+T= mg +F

so as F increases , T increases .

since T1 is gr8er than T by mg at all times, it will reach its elastic limit first and will break

in case 2 , when we pull it wid a je.rk , the impulse is greater than the elastic limit of the lower string . And b4 it could transfer this impulse to the upper string , it breks .

⏩The Answer is (B)

The Portion BC of the string will breakThePortionBCofthestringwillbreak.