Question

i want full solution please. of all parts

Answer 1

36 = (6×6)

here we see that 6 is making the same pair and no one is left ungrouped. so 36 is a pereft square.

2) 49 =( 7×7)
here we see that 7 is making the same pair and no one is left ungrouped. so 49 is a pereft square.

3) 64 =( 8×8)
here we see that 8 is making the same pair and no one is left ungrouped. so 64 is a perfect square.

4) 100 = 10×10

here we see that 10 is making the same pair and no one is left ungrouped. so 100 is a pereft square.




they all are perfect square.


sum of odd no.

36 = 1+3+5+7+9+11

49=1+3+5+7+9+11+13

64 = 1+3+5+7+9+11+13+15


100 = 1+3+5+7+9+11+13+15
+17+19

Answer 2

1) 36 = 17+19
2) 49 = 23+25+1
3) 64 = 31+31+1+1
4) 100 = 49+49+1+1



Hope this helps you