Question

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Answer 1

Answer:

Radius of 1st Bohr orbit in Li2+ ion = r/3

Explanation:

Let r be the radius of first Bohr orbit of hydrogen.

For an element of atomic number Z, radius of nth Bohr orbit is given by -

rn = r × n^2 / Z

For Li2+, Z = 3,

r' = r × 1^2 / 3

r' = r/3

Answer 2

Explanation:

Radius of any one electron system is r=Z0.0529 n2 nm, 

Radius of any one electron system is r=Z0.0529 n2 nm, where n= no. of orbit,  z = atomic no.

Radius of any one electron system is r=Z0.0529 n2 nm, where n= no. of orbit,  z = atomic no.For H- atom, z=1 and n=1

Radius of any one electron system is r=Z0.0529 n2 nm, where n= no. of orbit,  z = atomic no.For H- atom, z=1 and n=1Radius of first orbit of H-atom =10.0529×12=r

Radius of any one electron system is r=Z0.0529 n2 nm, where n= no. of orbit,  z = atomic no.For H- atom, z=1 and n=1Radius of first orbit of H-atom =10.0529×12=rFor Li, z=3 

Radius of any one electron system is r=Z0.0529 n2 nm, where n= no. of orbit,  z = atomic no.For H- atom, z=1 and n=1Radius of first orbit of H-atom =10.0529×12=rFor Li, z=3 Li+2 have the same number of electrons and orbits as in hydrogen atom.

Radius of any one electron system is r=Z0.0529 n2 nm, where n= no. of orbit,  z = atomic no.For H- atom, z=1 and n=1Radius of first orbit of H-atom =10.0529×12=rFor Li, z=3 Li+2 have the same number of electrons and orbits as in hydrogen atom.Here r=0.0529 nm, radius of first orbit of Li+2 = 30.0529×1 =30.0529

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