Math, asked by bittusingh02, 4 months ago

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Answered by Anonymous
7

\huge\color{pink}{\mathfrak{ᴀɴsᴡᴇʀ}}

1-(a) Monday= 1 hr

Tuesday= 1.5 hrs

Wednesday= 1 hr

Thursday= 1.5 hrs

Friday=1 hr

Saturday=1 hr

Sunday= 1.5 hrs

(b) On Tuesday, thurrsday and sunday Amit increased his practice.

(c) On friday and saturday his practice rsamined same.

(d) On Tuesday, Thursday and Sunday, he practiced more than one hour.

2-(a) When Shubham was born his weight was 2.5 kg.

(b) His weight increased fastest when he was born to 1 year. 7.8-2.5=5.3, he gained 5.3 kg weight from when he was born to when was of 1 year.

(c) (i) Weight gained between 5th and 8th year=19.5-15=4.5 kg

(ii) Weight gained between 7th and 10th year=24-18= 6kg

(d) Adding the weights and dividing by ten=

\frac{2.5 + 7.8 + 10 + 11.5 + 13.5  + 15 + 16+ 18 + 19.5 + 21.5 + 24}{10}  \\  \\  \frac{159.3}{10}  = 1593

{\underline{❥ʜᴏᴘᴇ  \: ɪᴛ \:  ʜᴇʟᴘs  \: ʏᴏᴜ.....}}

Answered by Anonymous
3

Answer:

Tuesday= 1.5 hrs

Wednesday= 1 hr

Thursday= 1.5 hrs

Friday=1 hr

Saturday=1 hr

Sunday= 1.5 hrs

(b) On Tuesday, thurrsday and sunday Amit increased his practice.

(c) On friday and saturday his practice rsamined same.

(d) On Tuesday, Thursday and Sunday, he practiced more than one hour.

2-(a) When Shubham was born his weight was 2.5 kg.

(b) His weight increased fastest when he was born to 1 year. 7.8-2.5=5.3, he gained 5.3 kg weight from when he was born to when was of 1 year.

(c) (i) Weight gained between 5th and 8th year=19.5-15=4.5 kg

(ii) Weight gained between 7th and 10th year=24-18= 6kg

(d) Adding the weights and dividing by ten=

\begin{gathered}\frac{2.5 + 7.8 + 10 + 11.5 + 13.5 + 15 + 16+ 18 + 19.5 + 21.5 + 24}{10} \\ \\ \frac{159.3}{10} = 1593\end{gathered}

10

2.5+7.8+10+11.5+13.5+15+16+18+19.5+21.5+24

10

159.3

=1593

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