Question

I want it urgently. . No stupid answers. . . I need step by step. .
find the zeroes of 5x^2-3-7x and verify the relationship between the zeroes and the coifficients.

Answer 1

hlo frnd hope this hlps u

Answer 2

let 6x2-7x-3 be p(x) =0
so,6x2-7x-3 =0
6x2-(9-2)x-3
6x2-9x+2x-3
(6x2-9x)(2x-3)
3x(2x-3)+1(2x-3)
(3x+1)(2x-3)=0

3x+1=0                                       2x-3=0

x=-1/3                                            x=3/2

sum of zeroes=-1/3+3/2  =7/6   =-b/a

product of zeroes=-1/3*3/2 = -3/6 or -1/2=c/a 

              hence verified.........